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Discussion of precise time and frequency measurement

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Re: [time-nuts] 10 MHz -> 16 MHz clock multiplier

E
EWKehren@aol.com
Thu, Jan 3, 2013 9:57 AM

Ulrich
you beat me to it, we have been using lately the ICS 512 and 570 for some
of our projects. If symmetry is not required 80 MHz and a 74 AC 90 will do,
if  symmetry is a must  the only low cost way I know is 160  MHz and a $ 2
MAX3000A gate array. We actually did a symmetrical divide by 3 and 5.
Bert Kehren

In a message dated 1/3/2013 4:11:45 A.M. Eastern Standard Time,
df6jb@ulrich-bangert.de writes:

Tom,

my 50 cents are: Use a 1 Euro expensive ICS503 in a  SOIC package to
generate
a 160 MHz signal from the 10 MHz without further  components needed (except
one c on the VCC and one on the input) and then  divide by 10. Expect a 50
ps
one sigma jitter on the output. You MUST use  capacitive coupling with an
external oscillator. Easily breadboarded! Have  used such a configuration to
generate phase locked clock signals for older  FPGAs without internal clock
generation.

Best regards
Ulrich

-----Ursprungliche Nachricht-----
Von:  time-nuts-bounces@febo.com
[mailto:time-nuts-bounces@febo.com] Im  Auftrag von Tom Van Baak
Gesendet: Mittwoch, 2. Januar 2013  19:55
An: Discussion of precise time and frequency measurement
Betreff: [time-nuts] 10 MHz -> 16 MHz clock multiplier

What's the simplest way to generate 16 MHz from 10 MHz? This
will be for clocking a microcontroller at 16 MHz given 10 MHz
(Cs/Rb/GPSDO). Low price and low parts count is a goal;
jitter is not  a concern but absolute long-term phase
coherence is a must.

The ICS525 (as in TAPR Clock-Block) is a good candidate but I
was wondering if there's something cheaper, less functional,
and maybe not SSOP. Any suggestions?

Thanks,
/tvb


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Ulrich you beat me to it, we have been using lately the ICS 512 and 570 for some of our projects. If symmetry is not required 80 MHz and a 74 AC 90 will do, if symmetry is a must the only low cost way I know is 160 MHz and a $ 2 MAX3000A gate array. We actually did a symmetrical divide by 3 and 5. Bert Kehren In a message dated 1/3/2013 4:11:45 A.M. Eastern Standard Time, df6jb@ulrich-bangert.de writes: Tom, my 50 cents are: Use a 1 Euro expensive ICS503 in a SOIC package to generate a 160 MHz signal from the 10 MHz without further components needed (except one c on the VCC and one on the input) and then divide by 10. Expect a 50 ps one sigma jitter on the output. You MUST use capacitive coupling with an external oscillator. Easily breadboarded! Have used such a configuration to generate phase locked clock signals for older FPGAs without internal clock generation. Best regards Ulrich > -----Ursprungliche Nachricht----- > Von: time-nuts-bounces@febo.com > [mailto:time-nuts-bounces@febo.com] Im Auftrag von Tom Van Baak > Gesendet: Mittwoch, 2. Januar 2013 19:55 > An: Discussion of precise time and frequency measurement > Betreff: [time-nuts] 10 MHz -> 16 MHz clock multiplier > > > What's the simplest way to generate 16 MHz from 10 MHz? This > will be for clocking a microcontroller at 16 MHz given 10 MHz > (Cs/Rb/GPSDO). Low price and low parts count is a goal; > jitter is not a concern but absolute long-term phase > coherence is a must. > > The ICS525 (as in TAPR Clock-Block) is a good candidate but I > was wondering if there's something cheaper, less functional, > and maybe not SSOP. Any suggestions? > > Thanks, > /tvb > > > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.