rot(p, a) = p * [ [ cos(a), sin(a) ], [-sin(a), cos(a)] ]; // Calculate the points for each polygon by generating N sides and rotating them. pts_a = [ for (i=[0:sides_a-1]) let(a=i*360/sides_a) each [ for (p=points(ir, 2*tan(360/sides_a/2)*ir, samples_per_side_a)) rot(p, a) ] ]; pts_b = [ for (i=[0:sides_b-1]) let(a=i*360/sides_b) each [ for (p=points(ir, 2

) circle(-points[i][2]); } function tangent(p1, p2) = let( r1 = p1[2], r2 = p2[2], dx = p2.x - p1.x, dy = p2.y - p1.y, d = sqrt(dx * dx + dy * dy), theta = atan2(dy, dx) + acos((r1 - r2) / d), xa = p1.x +(cos(theta) * r1), ya = p1.y +(sin(theta) * r1), xb = p2

Si usted no es el destinatario autorizado o por error recibe este mensaje, por favor informe al remitente y posteriormente bórrelo de su sistema sin conservar copia del mismo.

Si usted no es el destinarario de este mensaje, le suplicamos se lo notifique al remitente mediante un correo electrónico y que borre el presente mensaje y sus anexos de su computadora sin retener una copia de los mismos.

(pjsua_core.obj) : error LNK2019: símbolo externo > pjsip_timer_init_module sin resolver al que se hace referencia en la función > pjsua_init > pjnath_wince.lib(turn_sock.obj) : error LNK2001: símbolo externo > pj_sock_apply_qos2 sin resolver > pjsua_lib_wince.lib(pjsua_core.obj) : error LNK2019: símbolo externo > pj_sock_apply_qos2 sin resolver al que se hace

"Y" : "X", // slice in y dir for X axis case, and x dir otherwise sliced = vnf_slice(vnf, slicedir, bend_at), new_vert = [for(p=sliced[0]) f(p)] ) [new_vert,sliced[1]]; f = function(p) [p.x, p.y, 7*sin(4*p.x)+p.z+45]; rgn = union( rect([20,100]), back(50, p=trapezoid(w1=40, w2=0, h=20, anchor=FRONT)) ); rgnr = zrot(90, p

How can I then remove the X-Y plane surfaces of > the union. I would like to avoid inputting the points with their > coordinates directly to reduce overhead calculations and maintain things > parametric. So if you know the magic trick, I would really appreciate it!

Here's the "before" code, using flatten (I forget the original author): r = 10; h = 20; w = 2; s = 2; step = 4; vertices = [for (a=[0:step:360]) [ [r*cos(a), r*sin(a), 0], [r*cos(a), r*sin(a), h + s*sin(a*6)], [(r-w)*cos(a), (r-w)*sin(a), h + s*sin(a*6)], [(r-w)*cos(a), (r-w)*sin(a), 0] ]]; nv = 4*360/step; indices = [for (a=[0:360/step]) [ [(4*a+0

Friday, January 2, 2004, 8:18:46 AM, rwhb wrote: > Continuing to beat this subject to death I am still trying to grasp the > purpose of a Reverse Y adapter and paying $400 for it. If I tap two 30 amp > outlets from the marina somehow the adapter must know which side of the > 210-240V each input is in order to get me 210-240V?

Si usted no es el destinarario de este mensaje, le suplicamos se lo notifique al remitente mediante un correo electrónico y que borre el presente mensaje y sus anexos de su computadora sin retener una copia de los mismos.