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= r2 * math.sin(theta)) part1 -= part2 part2 = cylinder(2 * 50, 12).moved(x = 0, y = 0) part1 -= part2 show(part1) ###########The CadQuery code end############# Best regards, Youbao

Here's the program, in case anybody is interested: x=100; y=100; base = 1; randmax = 10; image = [ for(xi=[0:x]) [ for(yi=[0:y]) rands(0,randmax,1)[0] ], ]; //image = [ for(xi=[0:x]) // [ for(yi=[0:y]) let(r=max(norm([xi-x/2, yi-y/2]),0.01)) 10+5*sin(2000*r/norm([x,y])) ], // ]; points = [ for (xi=[0:x]) [xi, 0, 0],

May be in OpenSCAD2... 2016-08-18 18:26 GMT-03:00 Trygon : > Another way of approaching this type of problem is set out below.

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(2*pi*f*t) on an RF carrier fc > should result in two components at fc+f and fc-f, but outputting a > complex-valued baseband signal x(t) = exp(2*pi*f*t) should only result in > an fc+f component.

norm(p), atan2(p.y, p.x) ]; // Helix angle helix_a = atan2(pitch, helix_r*2*PI); // degrees per unit, along the circumference theta_scale = 360/(2*PI*helix_r); // Banana, algorithm A bananaA = function() [ for (a=[0:359]) torect2([helix_r, 0] + [r*cos(a), r * sin(a) * theta_scale / sin(helix_a)]) ]; // Banana, algorithm B bananaB = function

norm(p), atan2(p.y, p.x) ]; // Helix angle helix_a = atan2(pitch, helix_r*2*PI); // degrees per unit, along the circumference theta_scale = 360/(2*PI*helix_r); // Banana, algorithm A bananaA = function() [ for (a=[0:359]) torect2([helix_r, 0] + [r*cos(a), r * sin(a) * theta_scale / sin(helix_a)]) ]; // Banana, algorithm B bananaB = function

It would render almost instantly. > > > > On Wed, 9 Dec 2020 at 15:43, fred_dot_u via Discuss < > discuss@lists.openscad.org> wrote: > > Is the circle in the x/y plane or the x/z plane?

Just something like abs(z - sin(x) - sin(y)) <= d/2, where d is the desired thickness. I don't have time to compile the python integration for now so I just tried it with manifold sdf. The surface is not very smooth due to marching cubes used. It is probably better to do it with the method in BOSL2.